ProjectEuler Problem-1 Solution

Problem :

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.

Solution :

#include<iostream>
using namespace std;
#include<conio.h>

int main()
{
 int sum=0;
 for(int i=1;i<1000;i++)
 {
  if(i%3==0||i%5==0)
  {
  sum=sum+i;
     }
 }
 cout<<endl<<"Total   :"<<sum;
 return 0;
}